{"id":18155,"date":"2024-04-16T17:41:32","date_gmt":"2024-04-16T17:41:32","guid":{"rendered":"https:\/\/soicau2081.minhngocxoso.com\/?p=18155"},"modified":"2024-04-16T17:41:32","modified_gmt":"2024-04-16T17:41:32","slug":"bat-mi-cach-bat-tong-dac-biet-an-nhanh-thang-lon","status":"publish","type":"post","link":"https:\/\/soicaudephomnay.com\/bat-mi-cach-bat-tong-dac-biet-an-nhanh-thang-lon\/","title":{"rendered":"b\u1eadt m\u00ed c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t \u0103n nhanh th\u1eafng l\u1edbn"},"content":{"rendered":"
Khi tham gia ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc, c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u nh\u1eadn \u0111\u01b0\u1ee3c nhi\u1ec1u s\u1ef1 quan t\u00e2m c\u1ee7a tay ch\u01a1i c\u00e1 c\u01b0\u1ee3c chuy\u00ean nghi\u1ec7p. C\u00e1ch soi c\u1ea7u n\u00e0y \u0111\u01b0\u1ee3c \u0111\u00e1nh gi\u00e1 l\u00e0 \u0111\u01a1n gi\u1ea3n nh\u01b0ng mang l\u1ea1i hi\u1ec7u qu\u1ea3 c\u1ef1c k\u1ef3 cao. Ng\u01b0\u1eddi ch\u01a1i v\u1eeba k\u1ebft h\u1ee3p gi\u1eefa t\u01b0 duy nhanh nh\u1ea1y v\u1eeba k\u1ebft h\u1ee3p \u0111\u01b0\u1ee3c kinh nghi\u1ec7m ch\u01a1i l\u00f4 \u0111\u1ec1 c\u1ee7a m\u00ecnh \u0111\u1ec3 b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t. D\u01b0\u1edbi \u0111\u00e2y, ch\u00fang t\u00f4i s\u1ebd b\u1eadt m\u00ed c\u00e1ch soi t\u1ed5ng \u0111\u1eb7c bi\u1ec7t \u0103n nhanh th\u1eafng l\u1edbn cho anh em c\u00f9ng tham kh\u1ea3o nh\u00e9!<\/p>\n
D\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 \u0111\u1ec1 b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 c\u00e1ch \u0111\u01a1n gi\u1ea3n \u0111\u1ea7u ti\u00ean m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng. N\u1ebfu \u0111\u00e3 l\u00e0 tay ch\u01a1i c\u00e1 c\u01b0\u1ee3c chuy\u00ean nghi\u1ec7p, ch\u1eafc ch\u1eafn anh em s\u1ebd d\u1ec5 d\u00e0ng t\u00ecm ra \u0111\u01b0\u1ee3c quy lu\u1eadt l\u00f4 v\u1ec1 theo tu\u1ea7n ho\u1eb7c theo ng\u00e0y.<\/p>\n
Anh em c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o k\u1ebft x\u1ed5 s\u1ed1 l\u00e0 c\u1ed9ng 5 s\u1ed1 t\u1ea1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft qu\u1ea3 h\u00f4m qua r\u1ed3i c\u1ed9ng 1 s\u1ed1 \u0111\u00e1nh lu\u00f4n v\u00e0o ng\u00e0y k\u1ebf ti\u1ebfp. Con s\u1ed1 n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 \u0103n th\u01b0\u1edfng cao, anh em kh\u00f4ng ph\u1ea3i v\u1eadn \u0111\u1ed9ng tr\u00ed n\u00e3o qu\u00e1 nhi\u1ec1u. L\u01b0u \u00fd, n\u1ebfu h\u00f4m sau s\u1ed1 \u0111\u1eb7c bi\u1ec7t kh\u00f4ng v\u1ec1, anh em kh\u00f4ng n\u00ean nu\u00f4i con s\u1ed1 n\u00e0y nh\u00e9!<\/p>\n
Ngo\u00e0i ra, anh em c\u00f3 th\u1ec3 ch\u01a1i l\u00f4 \u0111\u1ec1 b\u1eb1ng c\u00e1ch soi l\u00f4 \u0111\u1ec1 c\u1ed9ng t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1eeb x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc c\u1ee7a ch\u1ee7 nh\u1eadt tu\u1ea7n n\u00e0y. R\u1ed3i nu\u00f4i ti\u1ebfp v\u00e0o ch\u1ee7 nh\u1eadt tu\u1ea7n k\u1ebf ti\u1ebfp. Theo chi\u1ebfn thu\u1eadt t\u1eeb d\u00e2n \u0111\u00e1nh l\u00f4, s\u1ed1 l\u00f4 n\u00e0y c\u00f3 c\u01a1 h\u1ed9i s\u1ebd v\u1ec1 v\u00e0o ng\u00e0y th\u1ee9 3, 4 \u1edf trong tu\u1ea7n.<\/p>\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t d\u1ef1a v\u00e0o quy lu\u1eadt c\u1ed9ng Pascal \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong c\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1 c\u1ee5 th\u1ec3 sau:<\/p>\n
Anh em ti\u1ebfn h\u00e0nh s\u1eed d\u1ee5ng 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 5 s\u1ed1 gi\u1ea3i nh\u1ea5t gh\u00e9p l\u1ea1i v\u1edbi nhau. K\u1ebf \u0111\u1ebfn, anh em h\u00e3y c\u1ed9ng 3 con s\u1ed1 n\u1eb1m li\u1ec1n nhau theo quy lu\u1eadt Pascal.<\/p>\n
\u0110\u1ed1i v\u1edbi tr\u01b0\u1eddng h\u1ee3p t\u1ed5ng l\u1ea1i l\u1edbn h\u01a1n 10, anh em h\u00e3y l\u1ea5y con s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb c\u1ed9ng cho t\u1edbi khi c\u00f2n l\u1ea1i 2 con s\u1ed1. Cu\u1ed1i c\u00f9ng, b\u1ea1n h\u00e3y s\u1eed d\u1ee5ng con s\u1ed1 \u0111\u00f3 \u0111\u1ec3 \u0111\u00e1nh t\u1ed5ng \u0111\u1eb7c bi\u1ec7t v\u00e0o ng\u00e0y h\u00f4m sau.<\/p>\n
L\u01b0u \u00fd, c\u00e1c s\u1ed1 c\u1ea7u \u0111\u01b0\u1ee3c nu\u00f4i ch\u1ec9 trong v\u00f2ng 3 ng\u00e0y.<\/p>\n
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V\u00ed d\u1ee5: V\u00e0o ng\u00e0y 29\/3\/2024, gi\u1ea3i nh\u1ea5t v\u00e0 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc v\u1ec1 l\u00e0 10454 v\u00e0 20464. Khi l\u00e0m ph\u00e9p t\u00ednh gh\u00e9p, anh em s\u1ebd \u0111\u01b0\u1ee3c con s\u1ed1 l\u00e0 1045420464. K\u1ebf \u0111\u1ebfn, anh em s\u1ebd c\u1ed9ng ch\u00fang l\u1ea1i theo quy lu\u1eadt Pascal v\u00e0 \u0111\u01b0\u1ee3c chu\u1ed7i c\u00e1c con s\u1ed1 sau: 1045420464- 240051499 \u2013 0451181 \u2013 64056538 \u2013 35818 \u2013 30 \u2013 496299 \u2013 8399 \u2013 128. Ti\u1ebfp theo, anh em h\u00e3y c\u1ed9ng ti\u1ebfp c\u00e1c chu\u1ed7i s\u1ed1 v\u00e0 ra 3 ng\u00e0y sau t\u1ee9c ng\u00e0y 1\/4\/2024 l\u00f4 s\u1ebd v\u1ec1 con s\u1ed1 30.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t d\u1ef1a v\u00e0o t\u00ednh l\u00f4, anh em c\u00f3 th\u1ec3 \u0111\u00e1nh li\u00ean t\u1ee5c trong 3 \u0111\u1ebfn 4 ng\u00e0y. N\u1ebfu ng\u00e0y h\u00f4m sau, anh em \u0111\u00e1nh kh\u00f4ng v\u1ec1 th\u00ec h\u00e3y ngh\u1ec9 1 ng\u00e0y r\u1ed3i ng\u00e0y k\u1ebf ti\u1ebfp l\u1ea1i \u0111\u00e1nh. C\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec3 soi t\u1ed5ng \u0111\u1eb7c bi\u1ec7t nh\u01b0 sau:<\/p>\n
Anh em c\u1ea7n ph\u1ea3i x\u00e1c \u0111\u1ecbnh m\u1ed1c ng\u00e0y b\u1eaft \u0111\u1ea7u th\u1ee9 nh\u1ea5t l\u00e0 XZ. \u0110\u1ebfn ng\u00e0y th\u1ee9 2 \u0111\u1ec1 v\u1ec1 con s\u1ed1 AB. Suy ra ta s\u1ebd c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh t\u1ed5ng \u0111\u1eb7c bi\u1ec7t d\u1ef1a v\u00e0o c\u00e1ch t\u00ednh l\u00f4 sau: X+Z=Q; A+B=C.<\/p>\n
N\u1ebfu Q<10, C<10, anh em h\u00e3y l\u1ea5y 10 \u2013 Q = D, 10 \u2013 C = H. V\u1eady, ng\u00e0y th\u1ee9 3 s\u1ebd l\u00e0 DH.<\/p>\n
N\u1ebfu Q<10, C<10, anh em l\u1ea5y 20 \u2013 Q = D, 20 \u2013 C = H.V\u1eady, ng\u00e0y th\u1ee9 3 ta \u0111\u00e1nh l\u00f4 s\u1ebd l\u00e0 DH.<\/p>\n
N\u1ebfu Q>10, C>10, anh em l\u1ea5y 20 \u2013 Q = D; 20 \u2013 C = H. V\u1eady, ng\u00e0y th\u1ee9 3 \u0111\u00e1nh l\u00f4 t\u01b0\u01a1ng t\u1ef1 \u1edf tr\u00ean l\u00e0 DH.<\/p>\n
N\u1ebfu Q<10, C>10, anh em l\u1ea5y 10 \u2013 Q = D, 20 \u2013 C = H. V\u1eady, anh em \u0111\u00e1nh HD v\u00e0o ng\u00e0y th\u1ee9 3.<\/p>\n
N\u1ebfu Q=10 ho\u1eb7c Q=0, n\u1ebfu C = 10 ho\u1eb7c C = 0 th\u00ec D,H b\u1eb1ng 0.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t qua s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a th\u1ee9 hai c\u0169ng \u0111\u01b0\u1ee3c nhi\u1ec1u d\u00e2n ch\u01a1i x\u1ed5 s\u1ed1 chuy\u00ean nghi\u1ec7p \u00e1p d\u1ee5ng. C\u00f4ng th\u1ee9c soi t\u1ed5ng \u0111\u1eb7c bi\u1ec7t n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh c\u1ee5 th\u1ec3 sau:<\/p>\n
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Anh em h\u00e3y l\u1ea5y con s\u1ed1 \u0111\u1ea7u gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 trong ng\u00e0y th\u1ee9 2 l\u00e0m t\u1ed5ng nu\u00f4i c\u1ea3 tu\u1ea7n. K\u1ebf \u0111\u1ebfn, anh em l\u1eadp d\u00e0n l\u00f4 \u0111\u1ec1 t\u1ed5ng chu\u1ea9n \u0111\u1ec3 nu\u00f4i. X\u00e1c su\u1ea5t tr\u00fang c\u1ee7a ph\u01b0\u01a1ng ph\u00e1p n\u00e0y t\u01b0\u01a1ng \u0111\u1ed1i cao, an hem n\u00ean t\u00ecm hi\u1ec3u th\u00eam v\u00e0 \u00e1p d\u1ee5ng nhu\u1ea7n nhuy\u1ec5n h\u01a1n.<\/p>\n
L\u1ea5y v\u00ed d\u1ee5 c\u1ee5 th\u1ec3 cho c\u00e1c b\u1ea1n hi\u1ec3u: V\u00e0o ng\u00e0y 1\/8\/2024 (th\u1ee9 2), gi\u1ea3i \u0111\u1eb7c bi\u1ec7t XSMB v\u1ec1 con s\u1ed1 05488. Anh em h\u00e3y l\u1ea5y con s\u1ed1 \u0111\u1ea7u ti\u00ean l\u00e0 con s\u1ed1 0 \u0111\u1ec3 l\u00e0m t\u1ed5ng chu\u1ea9n nu\u00f4i. K\u1ebf \u0111\u1ebfn, anh em s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c d\u00e0n l\u00f4 \u0111\u1ec1 g\u1ed3m c\u00e1c con s\u1ed1 sau: 00 \u2013 55 \u2013 191 \u2013 282 \u2013 373 \u2013 464.<\/p>\n
K\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 v\u00e0o ng\u00e0y 2\/8\/2024 s\u1ebd l\u00e0 55, 82, 91 v\u00e0 19.<\/p>\n
K\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 v\u00e0o ng\u00e0y 3\/8\/2024 s\u1ebd l\u00e0 82, 55 v\u00e0 37.<\/p>\n
K\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 ng\u00e0y 4\/8\/2024 s\u1ebd l\u00e0 19, 37, 55, 91 v\u00e0 82.<\/p>\n
K\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 ng\u00e0y 5\/8\/2024 s\u1ebd l\u00e0 19, 28, 55, 91 v\u00e0 64.<\/p>\n
Nh\u01b0 v\u1eady, th\u00f4ng qua c\u00e1c c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00f4 \u0111\u1ec1 Mi\u1ec1n B\u1eafc tr\u00ean. Ch\u00fang t\u00f4i hi v\u1ecdng s\u1ebd gi\u00fap c\u00e1c anh em c\u00f3 \u0111\u01b0\u1ee3c c\u00e1c k\u1ef9 n\u0103ng v\u00e0 ki\u1ebfn th\u1ee9c b\u1eaft t\u1ed5ng chu\u1ea9n x\u00e1c, d\u1ec5 tr\u00fang cao. Ch\u00fac anh em may m\u1eafn trong vi\u1ec7c soi t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc trong th\u1eddi gian t\u1edbi nh\u00e9!<\/p>\n