{"id":18605,"date":"2024-04-15T11:14:11","date_gmt":"2024-04-15T11:14:11","guid":{"rendered":"https:\/\/soicau2081.minhngocxoso.com\/?p=18605"},"modified":"2024-04-15T11:14:11","modified_gmt":"2024-04-15T11:14:11","slug":"soi-cau-tong-de-ca-nam-theo-tam-giac-pascal-dac-biet-hom-nay","status":"publish","type":"post","link":"https:\/\/soicaudephomnay.com\/soi-cau-tong-de-ca-nam-theo-tam-giac-pascal-dac-biet-hom-nay\/","title":{"rendered":"Soi c\u1ea7u t\u1ed5ng \u0111\u1ec1 c\u1ea3 n\u0103m theo tam gi\u00e1c Pascal \u0111\u1eb7c bi\u1ec7t h\u00f4m nay"},"content":{"rendered":"
Ng\u01b0\u1eddi ch\u01a1i n\u00ean ph\u00e2n bi\u1ec7t r\u00f5 r\u00e0ng \u0111\u1ec3 kh\u00f4ng nh\u1ea7m l\u1eabn v\u1edbi c\u00e1ch soi c\u1ea7u h\u00ecnh tam gi\u00e1c. S\u1eed d\u1ee5ng t\u1ed5ng Pascal c\u1ee7a Newton ch\u00ednh l\u00e0 \u1ee9ng d\u1ee5ng tuy\u1ec7t v\u1eddi gi\u00fap ng\u01b0\u1eddi ch\u01a1i nghi\u00ean c\u1ee9u l\u00f4 \u0111\u1ec1 kh\u00e1 chu\u1ea9n. Ch\u1ec9 c\u1ea7n b\u1ea1n \u00e1p d\u1ee5ng chu\u1ea9n c\u00e1ch \u0111\u00e1nh l\u00f4 gan, ki\u1ebfn th\u1ee9c to\u00e1n h\u1ecdc, \u0111\u1ed9 may m\u1eafn, kinh nghi\u1ec7m b\u1ea3n th\u00e2n \u0111\u1ec3 \u0103n \u0111\u01b0\u1ee3c con l\u00f4 th\u01a1m.<\/p>\n
\u0110\u1ea7u ti\u00ean, ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i nh\u1ea5t v\u00e0 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a x\u1ed5 s\u1ed1 h\u00f4m qua. Sau \u0111\u00f3, b\u1ea1n vi\u1ebft th\u00e0nh m\u1ed9t h\u00e0ng n\u1eb1m t\u1ea1i ph\u00eda d\u01b0\u1edbi \u0111\u00e1y tam gi\u00e1c. Gi\u1ea3 d\u1ee5 k\u1ebft qu\u1ea3 gi\u1ea3i nh\u1ea5t v\u1ec1 75178, c\u00f2n gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 15315. Ng\u01b0\u1eddi ch\u01a1i gh\u00e9p s\u1ed1 \u1edf trong hai gi\u1ea3i n\u00e0y th\u00e0nh d\u00e3y s\u1ed1 1 5 3 1 5 7 5 1 7 8. Khi \u0111\u01b0\u1ee3c d\u00e3y n\u1eb1m d\u01b0\u1edbi c\u1ee7a \u0111\u00e1y tam gi\u00e1c, ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng theo Pascal c\u1ee7a Newton \u0111\u1ec3 x\u00e2y d\u1ef1ng tam gi\u00e1c.<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i th\u1ef1c hi\u1ec7n c\u1ed9ng hai s\u1ed1 t\u1eeb tr\u00e1i qua ph\u1ea3i v\u1edbi nhau \u0111\u1ec3 \u0111\u01b0\u1ee3c d\u00e3y s\u1ed1 m\u1edbi. Ti\u1ebfp theo, \u0111i\u1ec1n l\u00ean h\u00e0ng th\u1ee9 hai. C\u1ee5 th\u1ec3 c\u1ed9ng c\u00e1c con s\u1ed1 1 + 5, 5 + 3, 3 + 1, 1 + 5\u2026 c\u1ee9 nh\u01b0 v\u1eady \u0111\u1ebfn h\u1ebft.<\/p>\n
Ta \u0111\u01b0\u1ee3c h\u00e0ng 2 \u0111\u00f3 l\u00e0 6 8 4 6 2 2 6 8 5. B\u1ea1n th\u1ef1c hi\u1ec7n nh\u01b0 v\u1eady th\u00e0nh h\u00ecnh tam gi\u00e1c Pascal \u0111\u1ebfn khi t\u00ecm \u0111\u01b0\u1ee3c hai con s\u1ed1 cu\u1ed1i c\u00f9ng. Con s\u1ed1 sau qu\u00e1 tr\u00ecnh c\u1ed9ng l\u00e0 89, nu\u00f4i ngay con s\u1ed1 b\u1ea1ch th\u1ee7 98 \u2013 89 t\u00f9y \u00fd.<\/p>\n
\u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p b\u1eaft t\u1ed5ng qua gi\u1ea3i \u0111\u1eb7c bi\u1ec7t, d\u1ef1a ch\u1ee7 y\u1ebfu theo c\u00f4ng th\u1ee9c to\u00e1n h\u1ecdc. Sau th\u1eddi gian nghi\u00ean c\u1ee9u, chuy\u00ean gia r\u00fat ra c\u00f4ng th\u1ee9 kh\u00e1 hi\u1ec7u qu\u1ea3. Ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ea5y hai gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 2 ng\u00e0y li\u00ean ti\u1ebfp \u0111\u1ec3 t\u00ednh. C\u00f4ng th\u1ee9c th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/p>\n
<\/p>\n
C\u1ed9ng to\u00e0n b\u1ed9 con s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y th\u1ee9 1 \u0111\u01b0\u1ee3c con s\u1ed1 AB.<\/p>\n
C\u1ed9ng to\u00e0n b\u1ed9 con s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y th\u1ee9 2 \u0111\u01b0\u1ee3c con s\u1ed1 CD.<\/p>\n
Ti\u1ebfp theo, b\u1ea1n l\u1ea5y C + D = F v\u00e0 A + B = E s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p s\u1ed1 F v\u00e0 E. Khi c\u00e1c b\u01b0\u1edbc v\u1eeba r\u1ed3i \u0111\u00e3 ho\u00e0n hi\u1ec7n, c\u00f3 m\u1ed9t v\u00e0i tr\u01b0\u1eddng h\u1ee3p sau x\u1ea3y ra:<\/p>\n
F > 10 v\u00e0 E < 10: Ch\u1ecdn 20 \u2013 F = K v\u00e0 10 \u2013 E = G. Con l\u00f4 ng\u00e0y ti\u1ebfp theo l\u00e0 KG, GK.<\/p>\n
F < 10 v\u00e0 E < 10: Ch\u1ecdn 10 \u2013 F = H v\u00e0 10 \u2013 E = G. Con l\u00f4 ng\u00e0y ti\u1ebfp theo l\u00e0 HG, GH.<\/p>\n
F > 10 v\u00e0 E > 10: Ch\u1ecdn 20 \u2013 F = K v\u00e0 20 \u2013 E = T. Con l\u00f4 ng\u00e0y ti\u1ebfp theo l\u00e0 KT, TK.<\/p>\n
F < 10 v\u00e0 E > 10: Ch\u1ecdn 10 \u2013 F = H v\u00e0 20 \u2013 E = T. Con l\u00f4 ng\u00e0y ti\u1ebfp theo l\u00e0 HT, TH.<\/p>\n
F v\u00e0 E \u0111\u1ec1u l\u00e0 0, ng\u01b0\u1eddi ch\u01a1i \u0111\u00e1nh ng\u00e0y h\u00f4m sau con l\u00f4 k\u00e9p 00.<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i n\u00ean nu\u00f4i nh\u1eefng c\u1eb7p l\u00f4 \u0111\u00e3 t\u00ednh to\u00e1n ph\u00eda tr\u00ean trong khung 3 ng\u00e0y. Do \u0111\u00f3, h\u00e3y chu\u1ea9n b\u1ecb ngu\u1ed3n v\u1ed1n \u1ed5n \u0111\u1ecbnh tr\u01b0\u1edbc khi b\u1eaft t\u1ed5ng \u0111\u1ec1. Tr\u01b0\u1eddng h\u1ee3p tr\u00fang l\u00f4, ng\u01b0\u1eddi ch\u01a1i n\u00ean d\u1eebng v\u00e0i ng\u00e0y m\u1edbi n\u00ean t\u00ednh to\u00e1n l\u1ea1i \u0111\u1ec3 nu\u00f4i ti\u1ebfp. N\u1ebfu kh\u00f4ng tr\u00fang sau ba ng\u00e0y, ng\u01b0\u1eddi ch\u01a1i n\u00ean d\u1eebng h\u1eb3n ba ng\u00e0y sau m\u1edbi \u0111\u00e1nh ti\u1ebfp.<\/p>\n
T\u00ecm nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng \u0111\u1ec1 chia \u0111\u01b0\u1ee3c h\u1ebft cho ba kh\u00e1 \u0111\u01a1n gi\u1ea3n. Ng\u01b0\u1eddi ch\u01a1i d\u1ef1a ho\u00e0n to\u00e0n v\u00e0o d\u1ea5u hi\u1ec7u to\u00e1n h\u1ecdc \u0111\u00e3 quy \u0111\u1ecbnh. B\u1ea1n c\u00f3 th\u1ec3 nh\u1eadn bi\u1ebft d\u1ec5 d\u00e0ng \u0111\u00f3 l\u00e0 con s\u1ed1 \u0111\u1ec1 \u0111\u00f3 c\u00f3 th\u1ec3 chia h\u1ebft \u0111\u01b0\u1ee3c cho 3 th\u00ec t\u1ed5ng c\u1ee7a ch\u00fang c\u0169ng t\u01b0\u01a1ng t\u1ef1. Ch\u1ec9 v\u1edbi c\u00e1c b\u01b0\u1edbc t\u00ednh \u0111\u01a1n gi\u1ea3n, b\u1ea1n \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c cho m\u00ecnh d\u00e0n t\u1ed5ng n\u00e0y.<\/p>\n
D\u00e0n t\u1ed5ng \u0111\u1ec1 chia \u0111\u01b0\u1ee3c h\u1ebft cho ba g\u1ed3m nh\u1eefng con s\u1ed1 \u0111\u00f3 l\u00e0 06, 09, 12, 15, 36, 39, 42, 45, 66, 69, 72, 84, 96, 75, 87, 90, 93, 00, 03, 18, 21, 24, 54, 57, 27, 30, 33, 48, 51, 60, 63, 78, 81, 99. D\u00e0n \u0111\u1ec1 n\u00e0y g\u1ed3m c\u00f3 34 con s\u1ed1, ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o \u0111\u00f3 \u0111\u1ec3 t\u00ecm \u0111\u01b0\u1ee3c cho m\u00ecnh con s\u1ed1 may m\u1eafn nh\u1ea5t. B\u00ean c\u1ea1nh \u0111\u00f3, \u0111\u1eebng qu\u00ean t\u00ednh to\u00e1n h\u1ee3p l\u00fd \u0111\u1ec3 t\u1ea1o th\u00e0nh nh\u1eefng d\u00e0n nh\u1ecf t\u1eeb t\u1ed5ng \u0111\u1ec1 l\u1edbn n\u00e0y.<\/p>\n
Th\u1eafc m\u1eafc t\u1ed5ng \u0111\u1ec1 l\u00e0 g\u00ec \u0111\u00e3 \u0111\u01b0\u1ee3c website ch\u00fang t\u00f4i chia s\u1ebb qua b\u00e0i vi\u1ebft tr\u00ean. Sau khi \u0111\u00e3 hi\u1ec3u r\u00f5 kh\u00e1i ni\u1ec7m c\u1ee7a t\u1ed5ng \u0111\u1ec1, b\u1ea1n ho\u00e0n to\u00e0n c\u00f3 th\u1ec3 t\u1ef1 l\u1eadp cho m\u00ecnh nh\u1eefng d\u00e0n \u0111\u1ec1 t\u1ed5ng th\u00edch h\u1ee3p. N\u1ebfu l\u00e0 ng\u01b0\u1eddi m\u1edbi, b\u1ea1n tham kh\u1ea3o nh\u1eefng d\u00e0n t\u1ed5ng \u0111\u1ec1 ph\u1ed5 bi\u1ebfn ch\u00fang t\u00f4i \u0111\u00e3 t\u1ed5ng h\u1ee3p.<\/p>\n<\/div>\n<\/div>\n